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what weight of sulfuric acid will be needed to react with 35.5g of ammonium in the pro. of amm. sulfate?
H2SO4 + 2 NH4+ >> (NH4)2SO4 + 2H+
Moles ammonium sulfate =
= 35.5 g /132.14 g/mol = 0.269
Moles H2SO4 = 0.269
mass H2SO4 = 0.269 mol x 98 g/mol = 26.4 g